Composition of Functions MCQ Quiz - Objective Question with Answer for Composition of Functions - Download Free PDF

Last updated on Apr 17, 2025

Latest Composition of Functions MCQ Objective Questions

Composition of Functions Question 1:

If g(x) = x2 + x – 1 and (gof)(x) = 4x2 – 10x + 5, then  is equal to

Answer (Detailed Solution Below)

Option 2 :

Composition of Functions Question 1 Detailed Solution

Explanation -

g(x) = x2 + x – 1

gof(x) = 4x2 – 10x + 5

g(f(x) = 4x2 – 10x + 5

f2(x) + f(x) – 1 = 4x2 – 10x + 5

Putting x = 5/4 and f(5/4) = t

t = -1/2 or f(5/4) = -1/2

Hence Option (2) is correct.

Composition of Functions Question 2:

For , let and . Then the value of is equal to:

Answer (Detailed Solution Below)

Option 4 :

Composition of Functions Question 2 Detailed Solution

Explanation:

  

Substitute the value of to get the following expression:

  

(3)

will be the same as

will be the same as

Composition of Functions Question 3:

Comprehension:

Direction : Consider the following for the items that follow : 

Let f o g(x) =cos2 √x and g o f(x) = |cos x|. 

Which one of the following is g(x)? 

  1. √x
  2. |x|
  3. x2
  4. x|x|

Answer (Detailed Solution Below)

Option 1 : √x

Composition of Functions Question 3 Detailed Solution

Explanation:

Given:

fog(x) =cos 2 √x and go f(x) = |cos x|. 

If we take option (c),

⇒ f(x) = cos2 x; then g(x) = √x 

⇒ fog(x) = cos 2 √x and go f(x) = 

= |cos2x|

Then f(x) = cos2 x

If f(x) = cos2 x then g(x) = √ x

∴ Option (a) is correct.

Composition of Functions Question 4:

Comprehension:

Direction : Consider the following for the items that follow : 

Let f o g(x) =cos2 √x and g o f(x) = |cos x|. 

Which one of the following is f(x)? 

  1. cos x
  2. cos x2
  3. cos2 x
  4. cos |x|

Answer (Detailed Solution Below)

Option 3 : cos2 x

Composition of Functions Question 4 Detailed Solution

Explanation:

Given:

fog(x) =cos 2 √x and go f(x) = |cos x|. 

If we take option (c),

⇒ f(x) = cos2 x; then g(x) = √x 

⇒ fog(x) = cos 2 √x and go f(x) = 

= |cos2x|

Then f(x) = cos2 x

∴ Option (c) is correct.

Composition of Functions Question 5:

f f(x) = 9x - 8√x such that g(x) = f(x) - 1, then which one of the following is correct?

  1. g(x) = 0 has no real roots 
  2. g(x) = 0 has only one real root which is an integer 
  3. g(x) = 0 has two real roots which are integers 
  4. g(x) = 0 has only one real root which is not an integer 

Answer (Detailed Solution Below)

Option 2 : g(x) = 0 has only one real root which is an integer 

Composition of Functions Question 5 Detailed Solution

Explanation:

Given:

f(x) = 9x - 8√x 

g(x) = f(x) - 1

Let x = t2

⇒ g(t2 ) = 9t2 – 8t – 1 = 0

⇒ t = 

⇒ x = 1 , 1/81

 g(x) = 0 has only one real root which is an integer.

∴ Option (b) is correct.

Top Composition of Functions MCQ Objective Questions

Let f, g : R → R be two functions defined as f(x) = |x| + x and g(x) = |x| - x ∀ x ∈ R. The (fog) (x) for x

  1. 0
  2. 4x
  3. -4x
  4. 2x

Answer (Detailed Solution Below)

Option 1 : 0

Composition of Functions Question 6 Detailed Solution

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Concept:

If f :A → B and g : C → D. Then (fog) (x) will exist if and only if the co-domain of g = domain of f i.e D = A and (gof) (x) will exist if and only if co-domain of f = domain of g i.e B = C.

In our case, the co-domain of g is R and the domain of f is also R  so (fog) (x) is defined.

Composition of function:

(fog) (x) = f[g(x)]

Calculations:

Given: f, g : R → R be two functions defined as f(x) = |x| + x and g(x) = |x| - x ∀ x ∈ R

Given, x

If(x) = |x| + x and g(x) = |x| - x 

Now, (fog) (x) = f[g(x)]

= |g(x)| + g(x)

For x

⇒ (fog) (x) = f[g(x)] = |g(x)| + g(x)

= 0 + 0 = 0

Let f : R → R be defined by f(x) = sin x, and g : R → R be defined by g(x) = x2. Find (f o g)(x).

  1. x2 sin x
  2. sin2 x
  3. sin x2
  4. 2x sin x

Answer (Detailed Solution Below)

Option 3 : sin x2

Composition of Functions Question 7 Detailed Solution

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Concept:

  • For two functions f(x) and g(x), (f o g)(x) is defined as f[g(x)].

 

Calculation:

f(x) = sin x and g(x) = x2.

∴ (f o g)(x) = f[g(x)] = sin [g(x)] = sin (x2) = sin x2.

If f(x) = 4x + 3, then what is f o f o f(-1) equal to?

  1. -1
  2. 0
  3. 1
  4. 2

Answer (Detailed Solution Below)

Option 1 : -1

Composition of Functions Question 8 Detailed Solution

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Concept:

For any two functions f and g, f o g is defined as f[g(x)].

Calculation:

Given that,

f(x) = 4x + 3   

Using the above concept

⇒ fof(x) = 4(4x + 3) + 3

⇒ fof(x) = 16x + 15 

Again using the same concept

⇒ fofof(x) = 16(4x + 3) + 15

fofof(x) = 64x + 63

Put x = -1 in the above function

⇒ fofof(-1) = 64(-1) + 63 = -1

∴  f o f o f(-1) equal to -1.

If f(x) = , x ≠ 1, then f{f(x)} = ? 

  1. -1/x
  2. 2/x

Answer (Detailed Solution Below)

Option 3 : x 

Composition of Functions Question 9 Detailed Solution

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Concept: 

Composition of function: Let f, and g be any functions then, f ∘ g(x) = f[g(x)]

Calculation:

Here, f(x) = 

f{f(x)} = 

= x

Hence, option (3) is correct.

If f (x) = 16x4, g(x) = x1/4 then gof (x) is 

  1. 16x
  2. 2x4
  3. 4x2
  4. 2x

Answer (Detailed Solution Below)

Option 4 : 2x

Composition of Functions Question 10 Detailed Solution

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Concept: 

Composition of function: Let f, and g be any functions then, f ∘ g(x) = f[g(x)]

Calculation:  

Given f (x) = 16x4 and g (x) = x1/4 

gof (x) = g[f(x)] =  

⇒ gof (x) =  

gof (x) = 2x

The correct option is 4. 

If f (x) = 8x, g(x) = x1/3 then gof (2) is ?

  1. 16
  2. 4
  3. 8
  4. 2

Answer (Detailed Solution Below)

Option 2 : 4

Composition of Functions Question 11 Detailed Solution

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Concept: 

Composition of function: Let f, and g be any functions then, f ∘ g(x) = f[g(x)]

Calculation:  

Given f (x) = 8x3 and g (x) = x1/3 

gof (x) = g[f(x)] =  

⇒ gof (x) =  

 gof (x) = 2x 

Now put x = 2

So, gof (2) = 4 

The correct option is 2. 

If f(x) = ex and g(x) = loge x then the value of fog(1) is

  1. 0
  2. 1
  3. -1
  4. None of these

Answer (Detailed Solution Below)

Option 2 : 1

Composition of Functions Question 12 Detailed Solution

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Concept: 

Composition of function: Let f, and g be any functions then, f ∘ g(x) = f[g(x)]

 

Calculations:

Given, f(x) = ex and g(x) = loge x

Now, f ∘ g(x) = f[g(x)]

= eg(x)

= eloge x

= x                (∵ eloge x = x)

f ∘ g(x) = x

Put x = 1, we get

fog(1) = 1

Given f(x) =  and g(x) = , then what is f[g(x)] equal to?

  1. None of the above

Answer (Detailed Solution Below)

Option 4 : None of the above

Composition of Functions Question 13 Detailed Solution

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Concept:

Composition of function: fog(x) = f(g(x)), it means that the value of x for the function f(x) is g(x).

Example: Suppose f(x ) = x + 2 and g(x) = 2x. Then f(g(x)) = g(x) + 2 = 2x + 2

 

Calculation:

Given that, f(x) =  and g(x) =

f[g(x)] =

Hence, option (4) is correct.

Mistake Points
For option C, the Numerator should be (4x + x2 + 4) but it is given as (2x + x2 + 4). Therefore, option 4 is correct answer.

Let f(x) = px + q and g(x) = mx + n. Then f (g(x)) = g (f(x)) is equivalent to

  1. f(p) = g(m)
  2. f(q) = g(n)
  3. f(n) = g(q)
  4. f(m) = g(p)

Answer (Detailed Solution Below)

Option 3 : f(n) = g(q)

Composition of Functions Question 14 Detailed Solution

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Calculation:

Given: f(x) = px + q and g(x) = mx + n

f (g(x)) = g (f(x))

f (mx + n) = g (px + q)

p (mx + n) + q = m (px + q) + n

pmx + pn + q = pmx + mq + n

pn + q = mq + n

f (n) = g (q)

∴ Option 3 is correct answer.

Answer (Detailed Solution Below)

Option 4 :

Composition of Functions Question 15 Detailed Solution

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Calculation:

Here, f(x) + 2f() =                 ....(1)

Replace x by , we get 

f() + 2f(x) = x                          ....(2)

Adding (1) and (2), we get  

 3f(x) + 3f()) = x +                ....(3)

Now, subtracting (1) from (2), we get

f(x) - f() = x - 

Multiplying by 3,

3f(x) - 3f() = 3x -                   ....(4)

Now, adding (3) and (4) we get 

6f(x) = 4x - 

f(x) = 

Hence, option (4) is correct.

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