12 Men are assigned a job to be finished in 30 days. After 10 days it is observed that only 1/6^thof the job is completed. How many extra men are required to be deployed to do the rest of the job so that the job is completed within scheduled time?

Question

Question

This question was previously asked in

UGC NET Paper 1: Held on 21st June 2023 Shift 2

Answer 1

Given:

In 10 days 1/6^th of the work completed by 12 men.

Concept used:

\(\frac{M_1 × D_1}{W_1} = \frac{M_2× D_2}{W_2}\) , where M₁ and M₂ are number of workers, D₁ and D₂ are time and W₁ and W₂ are work

Calculation:

Here, 10 days 1/6th of the work completed by 12 men, then remaining 5/6^th work will be completed in remaining 20 days, then

\(\frac{12× 10}{\frac{1}{6}} = \frac{M_2× 20}{\frac{5}{6}}\)

⇒ 12 × 10 × 5 = M₂ × 20

⇒ M₂ = 600/20

⇒ M2 = 30

Now, extra men deployed (30 - 12) = 18

∴ The correct answer is 18