Question
Download Solution PDFA 15 V AC source is applied to a load impedance of (3 – j4) Ω. Find the load current.
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept:
Considered impedance (Z = R ± jX) connected to the voltage source V shown below:
Current flowing through the circuit is given as
In conjugate form current is given as,
Where,
And,
Where ϕ is the phase angle between voltage and current.
R is Resistance in Ω.
X is Inductive or Capacitive Reactance in Ω.
|Z| is the magnitude of Impedance.
|I| is the magnitude of Current.
Calculation:
Given, Z = (3 – j4) Ω and V = 15 V
∴
From the above concept,
Important Points
cos (53.13) = sin (36.86) = 0.6 = 3/5
sin (53.13) = cos (36.86) = 0.8 = 4/5
Alternate MethodWe have,
V = 15 volts
Z = (3 - j4) Ω
Hence,
I =
It can be written as,
I =
Hence,
I = (1.8 + j2.4) A
Last updated on Jun 16, 2025
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