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A and B can do a job in 25 days and 18 days, respectively. A works alone for 4 days and leaves. The number of days required by B to complete the remaining job is:

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RRB NTPC Graduate Level CBT-I Official Paper (Held On: 06 Jun, 2025 Shift 1)
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  1. 15
  2. 17
  3. 16
  4. 15

Answer (Detailed Solution Below)

Option 4 : 15
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Detailed Solution

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Given:

A can do the job in 25 days

B can do the job in 18 days

A works for 4 days and leaves

Calculation:

Assume total work = LCM of 25 and 18 = 450 units

A's rate = 450 ÷ 25 = 18 units/day

B's rate = 450 ÷ 18 = 25 units/day

⇒ Work done by A in 4 days = 4 × 18 = 72 units

⇒ Remaining work = 450 − 72 = 378 units

⇒ Time for B = 378 ÷ 25 = 15 days

∴ B will take 15 days to finish the job.

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