Question
Download Solution PDFA can finish a work in 18 days and B can do the same work in 15 days. B worked for 10 days and left the job. In how many days will A complete he remaining work?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFGiven:
A can finish the work in 18 days.
B can finish the work in 15 days.
B worked for 10 days and then left the job.
Formula used:
Efficiency = Work ÷ Time
Work done by B = B's efficiency × Time worked
Remaining work = Total work - Work done by B
Time taken by A = Remaining work ÷ A's efficiency
Calculations:
Let's assume the total work is 90 units (LCM of 18 and 15).
Efficiency of A = 90 ÷ 18 = 5 units per day
Efficiency of B = 90 ÷ 15 = 6 units per day
Work done by B in 10 days = 6 × 10 = 60 units
Remaining work = 90 - 60 = 30 units
Time taken by A to complete the remaining work = 30 ÷ 5 = 6 days
∴ A will complete the remaining work in 6 days.
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