Question
Download Solution PDFA Hartley oscillator uses L1 = 2 mH and L2 = 1.5 mH. The range of capacitance so that the frequency of oscillation can be varied between 1000 kHz to 2000 kHz are:
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFIn Hartley Oscillator,
\(f_0=\frac{1}{2\pi \sqrt{(L_1+L_2)C}}\)
\(C=\frac{1}{4\pi^2f_0^2{(L_1+L_2)}}\)
If f0 = 1000 kHz ⇒ C = 7.2 pF
If f0 = 2000 kHz ⇒ C = 1.8 pF
(or) \(\frac{C_2}{C_1}=\left(\frac{f_{01}}{f_{02}}\right)^2=\frac{1}{4}\)
⇒ \(\frac{C_{max}}{C_{min}}=4\)
This ratio matches with option (a)
Last updated on Jul 2, 2025
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