Question
Download Solution PDFA helical compression spring of stiffness K is cut into two pieces, each having equal number of turns and kept side-by-side under compression. The equivalent spring stiffness of this new arrangement is equal to
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept:
When a spring is cut into two equal halves, the stiffness of each half becomes double because stiffness is inversely proportional to the length:
\( K' = 2K \)
If these two springs are placed side-by-side (i.e., in parallel), the equivalent stiffness becomes:
\( K_{\text{eq}} = 2K + 2K = 4K \)
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