A solid sphere of radius 3 cm is melted to form a hollow cylinder of height 4 cm and external diameter 10 cm. What is the thickness of the cylinder?

This question was previously asked in
CDS Elementary Mathematics 3 Sep 2023 Official Paper
View all CDS Papers >
  1. 0.42 cm
  2. 0.46 cm
  3. 0.50 cm
  4. 1.00 cm

Answer (Detailed Solution Below)

Option 4 : 1.00 cm
Free
UPSC CDS 01/2025 General Knowledge Full Mock Test
8.1 K Users
120 Questions 100 Marks 120 Mins

Detailed Solution

Download Solution PDF

Given:

A solid sphere of radius 3 cm is melted to form a hollow cylinder of height 4cm & external diameter 10cm.

Formula used:

Volume of sphere = 4/3π r3

Volume of hollow cylinder = π(R- r2)h

Thickness of cylinder = External radius - Internal radius

Calculation:

According to the question,

External diameter = 10cm

External radius = 10/2= 5cm

Volume of sphere = Volume of hollow cylinder

⇒ 4/3π (33) = π(52-r2)4

⇒ 9 = 25 - r2

⇒ r2 = 16

⇒ r = 4

Thickness of cylinder = 5 - 4 = 1 cm

∴ The thickness of the cylinder is 1 cm.

Latest CDS Updates

Last updated on Jun 26, 2025

-> The UPSC CDS Exam Date 2025 has been released which will be conducted on 14th September 2025.

-> Candidates had applied online till 20th June 2025.

-> The selection process includes Written Examination, SSB Interview, Document Verification, and Medical Examination.  

-> Attempt UPSC CDS Free Mock Test to boost your score.

-> Refer to the CDS Previous Year Papers to enhance your preparation. 

More Mensuration Questions

Get Free Access Now
Hot Links: teen patti real cash 2024 teen patti octro 3 patti rummy all teen patti master