Question
Download Solution PDFA steel bar of 20 mm × 20 mm square crosssection is subjected to an axial compressive load of 200 kN. If the length of the bar is 1 m and E =100 GPa, the contraction of the bar will be
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept:
Elongation or Contraction in the rod when an axial force is applied is given by:
where P is axial load, L is the length of the bar, δL is the elongation in the length of the bar, A is a cross-section area of the bar, E is Young's modulus of elasticity.
Calculation:
Given:
P = 200 kN, L = 1 m, A = 20 mm × 20 mm, E = 100 GPa
contraction of the bar
Hence the required contraction of the bar will be 5 mm.
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