A tank contains oil of specific gravity of 0.9, The depth of the point below free surface is (where, the pressure intensity is 9 kg(f)/cm²)

Question

Question

This question was previously asked in

BPSC AE Paper IV General Engineering 19 Dec 2024 Official Paper

Attempt Online

Answer 1

Concept:

Pressure at a depth in a fluid is given by:

\( P = \rho g h \)

Where,

Calculation:

Given specific gravity: \( SG = 0.9 \Rightarrow \rho = 0.9 \times 1000 = 900~kg/m^3 \)

Pressure: \( P = 9~kgf/cm^2 = 9 \times 10^4~kgf/m^2 \)

\( 1~kgf = 9.81~N \Rightarrow P = 9 \times 10^4 \times 9.81 = 8.829 \times 10^5~N/m^2 \)

\( h = \frac{P}{\rho g} = \frac{8.829 \times 10^5}{900 \times 9.81} = 100~m \)