A two- dimensional flow field is defined as \(\vec V = \vec ix - \vec jy\) the equation of the streamline passing through the point (1, 2) is 

  1. xy + 2 = 0
  2. x2y + 2 = 0
  3. xy – 2 = 0
  4. x2y – 2 = 0
  5. xy2 - 2 = 0

Answer (Detailed Solution Below)

Option 3 : xy – 2 = 0
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Detailed Solution

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Concept:

Streamline: It is the line along which stream function ψ remains constant.

If ψ = f (x,y)

dψ = 0

\(d\psi = \frac{{\partial \psi }}{{\partial x}}dx + \frac{{\partial \psi }}{{\partial y}}dy\)

For streamline dψ = 0

\( vdx - udy = 0\)

∴ \( \frac{{dx}}{u} = \frac{{dy}}{v} \)

Calculation:

Given:

\(\vec V = \vec ix - \vec jy\)

So, u = x and v = -y

Streamline equation: \(\frac{{dx}}{u} = \frac{{dy}}{v}\)

\(\frac{{dx}}{x} = \frac{{dy}}{{ - y}}\)

Integrating both side

ln x = -ln y + ln c

xy = c

Given x = 1, y = 2

so, c = 2

so equation is xy – 2 = 0

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