Question
Download Solution PDFAbha can do some work in 10 days, Billu can do it in 20 days and Chintu can do it in 40 days. They start working in turns with Abha starting to work on the first day followed by Billu on the second day and by Chintu on the third day and again by Abha on the fourth day and so on, till the work is completed fully. Find the time taken (approx.) to complete the work fully.
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFGiven:
Abha can complete the work in 10 days
Billu in 20 days
Chintu in 40 days
Calculation:
Take LCM of 10, 20, and 40 to assume total work = 40 units (LCM method)
Work per day:
Abha: 40 ÷ 10 = 4 units/day
Billu: 40 ÷ 20 = 2 units/day
Chintu: 40 ÷ 40 = 1 unit/day
Work in 3-day cycle:
Day 1 (Abha) + Day 2 (Billu) + Day 3 (Chintu) = 4 + 2 + 1 = 7 units in 3 days
Full 5 cycles (15 days) → 5 × 7 = 35 units
Remaining work = 40 − 35 = 5 units
Next day (Day 16) → Abha works = 4 units → total = 39 units
Next day (Day 17) → Billu works = 2 units, but only 1 unit left → he needs only 0.5 day
Total time taken = 16 full days + 0.5 day = 16.5 days ≈ 16 days
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