An object is placed 100 cm in front of a concave mirror. The real image of the object is formed 50 cm in front of the mirror. What is the object's magnification ?

  1. -0.5
  2. -1.0
  3. 0.5
  4. 1.0

Answer (Detailed Solution Below)

Option 1 : -0.5
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CONCEPT:

  • Mirror formula: The expression which shows the relation between object distance (u)image distance (v), and focal length (f) is called mirror formula.

\(\frac{1}{v} + \frac{1}{u} = \frac{1}{f}\)

Linear magnification (m):

  • It is defined as the ratio of the height of the image (hi) to the height of the object (ho).

i.e. \(m = \frac{{{h_i}}}{{{h_o}}}\)

  • The ratio of image distance to the object distance is called linear magnification.

i.e. \(m = \frac{{image\;distance\;\left( v \right)}}{{object\;distance\;\left( u \right)}} = - \frac{v}{u}\)

CALCULATION:

Given - u = -100 cm and v = -50 cm

  • As we know that the ratio of image distance to the object distance is called linear magnification.

 \(\Rightarrow m = \frac{{image\;distance\;\left( v \right)}}{{object\;distance\;\left( u \right)}} = - \frac{v}{u}\)

\(\Rightarrow m = -\frac{-50}{-100}=-0.5\)

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