ত্রিভুজ ABC-এর মধ্যমা AD বর্ধিত করা হলো এবং তার উপর লম্ব CF টানা হলো। BE হলো AD-এর উপর লম্ব। যদি BC = 34 cm এবং DF = 8 cm হয়, তাহলে BE-এর দৈর্ঘ্য (cm এ) কত?

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SSC Selection Post 2024 (Graduate Level) Official Paper (Held On: 20 Jun, 2024 Shift 3)
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  1. 17
  2. 9
  3. 15
  4. 19

Answer (Detailed Solution Below)

Option 3 : 15
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প্রদত্ত:

BC = 34 cm

DF = 8 cm

ব্যবহৃত সূত্র:

একটি ত্রিভুজে, মধ্যমা বাহুকে সমদ্বিখণ্ডিত করে।

গণনা:

প্রদত্ত BC = 34 cm

ত্রিভুজ BED এবং CDF তে

BD = CD (কারণ AD মধ্যমা)

∠E = ∠F

BDE = ∠CDF (বিপ্রতীপ কোণ)

অতএব ত্রিভুজ BED এবং CDF সর্বসম

অতএব, BE = CF

ত্রিভুজ BED তে:

(BD)2 = (BE)2 + (ED)2

⇒ (17)2 = (BE)2 + (8)2

⇒ 289 = 64 + (BE)2

⇒ (BE)2 = 289 - 64

⇒ BE =

⇒ BE = 15 cm

অতএব, BE এর দৈর্ঘ্য 15 cm।

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