Question
Download Solution PDFDrag coefficient is independent of reynold's number in zone.
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFExplanation:
The ratio of wall shear stress at any distance x from the leading edge to dynamic pressure is called the local drag coefficient.
As per Blasius' Results for a laminar boundary on a smooth plate
(i) Local drag coefficient is given by
\(C_{fx}=\frac{0.664}{R_{eL}}^{1/2}\)
(ii) Average drag coefficient, CD = 2 x Cfx
\(C_{D}=\frac{1.328}{R_{eL}^{1/2}}\)
Additional Information
| Laminar | Turbulent |
| 1. \(\frac{\delta }{x} = \frac{5}{{\sqrt {{{{\mathop{\rm Re}\nolimits} }_x}} }}\) | 1. \(\frac{\delta }{x} = \frac{{0.376}}{{{{\left( {{{{\mathop{\rm Re}\nolimits} }_x}} \right)}^{1/5}}}}\) |
| 2. \({C_{fx}} = \frac{{0.664}}{{{{\left( {{R_{ex}}} \right)}^{1/2}}}}\) | 2. \({C_{fx}} = \frac{{0.059}}{{{{\left( {{R_{ex}}} \right)}^{1/5}}}}\) |
| 3. \({C_D} = \frac{{1.328}}{{{{\left( {{R_{eL}}} \right)}^{1/2}}}}\) | 3. \({C_{fx}} = \frac{{0.074}}{{{{\left( {{R_{eL}}} \right)}^{1/5}}}}\) |
So Drag coefficient is dependent on Reynold's number in all Zones.
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