Question
Download Solution PDFFigure shows the P-V diagram of an ideal gas. The work done by the gas in the process ABCDA is:
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept:
\(W = \mathop \smallint \limits_{{v_1}}^{{v_2}} pdV = P\left( {{V_2} - {V_1}} \right)\)
Work Done = Area under P – V diagram
Calculation:
Given:
Work done = Area of Parallelogram ABCDA
Area of parallelogram = 1/2 × (Sum of parallel sides) × height
Work done = Area of Parallelogram ABCDA = 1/2 × (AB + CD) × BC
⇒ 1/2 × (V + 2V) × P = 1.5PV
Last updated on May 28, 2025
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