Find the coordinates of the focus of the parabola x² = 6y.

Question

Question

This question was previously asked in

Navik GD 22 March 2021 Memory Based Paper (Section I + II)

Answer 1

Concept:

Equation of parabola along Y-axis:

x² = ± 4ay, Focus (0, ± a)

Solution:

The given equation of a parabola is x² = 6y

On comparing this equation with x² = 4ay, we obtain

4a = 6 ⇒ a = \(\frac{3}{2}\)

Therefore, the coordinates of the focus F = (0, a) ⇒ \(\left ( 0,\frac{3}{2} \right )\)

∴ The correct option is (2)