Find the divisor, given that the dividend is 2200, remainder is 13, and the divisor is one-third of the quotient.

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BSSC Group D Official Paper (Held On: 11 May, 2025)
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  1. 24
  2. 27
  3. 25
  4. None of these

Answer (Detailed Solution Below)

Option 2 : 27
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BSSC Group D (कार्यालय परिचारी) ST (Class 8th) 1: General Awareness
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Detailed Solution

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Given:

Dividend = 2200

Remainder = 13

Divisor = one-third of the Quotient

Formula used:

Dividend = Divisor × Quotient + Remainder

Divisor = Quotient ÷ 3

Calculation:

2200 = Divisor × Quotient + 13

⇒ 2200 - 13 = Divisor × Quotient

⇒ 2187 = Divisor × Quotient

Divisor = Quotient ÷ 3

⇒ 2187 = (Quotient ÷ 3) × Quotient

⇒ 2187 = Quotient2 ÷ 3

⇒ Quotient2 = 2187 × 3

⇒ Quotient2 = 6561

⇒ Quotient = √6561

⇒ Quotient = 81

Divisor = Quotient ÷ 3

⇒ Divisor = 81 ÷ 3

⇒ Divisor = 27

∴ The correct answer is option (2).

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Last updated on Jun 5, 2025

-> The BSSC Group D Written Test Response Sheet has been released at the official portal.

-> The examination was conducted on 11th May 2025.

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