Question
Download Solution PDFFor the different orifices, depending on the shape and size of orifice and the head under which flow takes place, The value of Coefficient of velocity Cv is varies from
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFExplanation:
Coefficient of velocity:
- It is defined as the ratio of the actual velocity of the jet at veena contracta V to the theoretical velocity Vth
Experimentally it is determined by using the following relation
where x= Horizontal distance
y= vertical distance
H= constant headwater
Generally, the value of Cy varies from 0.95 to .99 for different orifices depending upon their size, shape, head etc.
for sharp-edged orifices, the value of Cy is 0.98.
Types of tubes | Cc | Cv |
Rounded | 1 | 0.98 |
Sharp-edged | 0.62 | 0.98 |
Short tube | 1 | 0.8 |
Borda tube | 0.52 | 0.98 |
Last updated on Jul 1, 2025
-> JKSSB Junior Engineer recruitment exam date 2025 for Civil and Electrical Engineering has been rescheduled on its official website.
-> JKSSB JE exam will be conducted on 31st August (Civil), and on 24th August 2025 (Electrical).
-> JKSSB JE application form correction facility has been started. Candidates can make corrections in the JKSSB recruitment 2025 form from June 23 to 27.
-> JKSSB JE recruitment 2025 notification has been released for Civil Engineering.
-> A total of 508 vacancies has been announced for JKSSB JE Civil Engineering recruitment 2025.
-> JKSSB JE Online Application form will be activated from 18th May 2025 to 16th June 2025
-> Candidates who are preparing for the exam can access the JKSSB JE syllabus PDF from official website of JKSSB.
-> The candidates can check the JKSSB JE Previous Year Papers to understand the difficulty level of the exam.
-> Candidates also attempt the JKSSB JE Mock Test which gives you an experience of the actual exam.