Question
Download Solution PDFFor the network shown above, using the network reduction technique, Req = ________.
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept
The series equivalent of two resistances is given by:
Req = R1 + R2
The parallel equivalent of two resistances is given by:
\(R_{eq}={R_1R_2\over R_1+R_2}\)
Calculation
From the figure, 1 Ω and 5 Ω are in series.
R = 6 Ω
From the figure, 6 Ω and 3 Ω are in parallel.
\(R={6\times 3\over 6+3}=2\space Ω\)
4 Ω and 6 Ω are in parallel.
\(R={6\times 4\over 6+4}=2.4\space Ω\)
Req = 4 + 8 + 2.4
Req = 14.4 Ω
Last updated on Jul 23, 2025
-> MPPGCL Junior Engineer recruitment 2025 apply online link has been activated. Interested candidates can submit their online application form, from 23rd July to 21st August 2025.
-> MPPGCL Junior Engineer Notification 2025 has been released for various fields of post (Advt No. 3233).
-> MPPGCL has announced a total of 90 vacancies for Civil, Mechanical, Electrical, and Electronics Engineering (Junior Engineer).
-> The selection process includes a Computer Based Test and Document Verification.
-> Candidates can check the MPPGCL JE Previous Year Papers which helps to understand the difficulty level of the exam.