[(9)3 × (?)2] ÷ 21 = 1701

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CSIR-CLRI JSA 2024 Official Paper-I (Held On: 16 Feb, 2025)
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  1. 6
  2. 3
  3. 11
  4. 7

Answer (Detailed Solution Below)

Option 4 : 7
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दिया गया है:

[(9)3 × (?)2] ÷ 21 = 1701

प्रयुक्त सूत्र:

(?)2 को अलग करने और चरण दर चरण हल करने के लिए BODMAS का प्रयोग करें

गणना:

⇒ [(9)3 × (?)2] ÷ 21 = 1701

⇒ (729 × (?)2) ÷ 21 = 1701

⇒ 729 × (?)2 = 1701 × 21

⇒ 729 × (?)2 = 35721

⇒ (?)2 = 35721 ÷ 729

⇒ (?)2 = 49

⇒ ? = √49 = 7

∴ लुप्त संख्या 7 है। 

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