Question
Download Solution PDFएक 2-ध्रुव, 50 Hz, 11 kV, 100 MVA वाले आवर्तित्र में 10,000 kg.m2 का जड़त्वाघूर्ण है। तो जड़त्व स्थिरांक का मान, H क्या है?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFसंकल्पना:
जड़त्व स्थिरांक, H = (MJ में संग्रहित गतिज ऊर्जा)/(मशीन की रेटिंग)
संग्रहित गतिक ऊर्जा
I जड़त्वाघूर्ण है।
ω = 2πf
गणना:
P = 2, f = 50 Hz, V = 11 kV, P = 100 MVA
जड़त्वाघूर्ण, I = 10,000 kg-m2
ω = 2πf = 2π (50) = 100 π
= 314.15 रेडियन/सेकेंड
संग्रहित गतिक ऊर्जा
= 4.93 × 108J = 493 MJ
⇒ H = 4.93 सेकेंड
Last updated on Jun 23, 2025
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