64 tan2θ + 81 cosec2θ + 76 का न्यूनतम मान ज्ञात कीजिए। 

  1. 101 
  2. 201
  3. 301
  4. 401 

Answer (Detailed Solution Below)

Option 3 : 301
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Detailed Solution

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प्रयुक्त सूत्र :

1 + tan2θ = sec2θ 

asec2θ + bcosec2θ का न्यूनतम मान (√a + √b)है

गणना :

64 tan2θ + 81 cosec2θ + 76 = 64 tan2θ + 81 cosec2θ + 64 + 12

⇒ 64 + 64 tan2θ + 81 cosec2θ + 12

⇒ 64(1 + tan2θ) + 81 cosec2θ + 12 

⇒ 64 sec2θ + 81 cosec2θ + 12

64 sec2θ + 81 cosec2θ का न्यूनतम मान = (√64 + √81)

⇒ (8 + 9)2

⇒ 289

अब,

64 sec2θ + 81 cosec2θ + 12 का न्यूनतम मान = 289 + 12

⇒ 301

64 tan2θ + 81 cosec2θ + 76 का न्यूनतम मान 301 है। 

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