यदि 50 प्रेक्षणों x1, x2, …,x50 का माध्य और मानक विचलन दोनों 16 के बराबर हैं, तो (x1 - 4)2, (x2 - 4)2,….(x50 - 4)2 का माध्य है:

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JEE Mains Previous Paper 1 (Held On: 10 Apr 2019 Shift 2)
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  1. 400
  2. 380
  3. 525
  4. 480

Answer (Detailed Solution Below)

Option 1 : 400
Free
JEE Main 04 April 2024 Shift 1
90 Qs. 300 Marks 180 Mins

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दिया गया है, 50 प्रेक्षणों का माध्य और मानक विचलन 16 के बराबर है।

माध्य,

मानक विचलन,

256 x 2

अभीष्ट माध्य

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