Question
Download Solution PDFआकृति में, एक वृत्त की जीवा AB और CD एक-दूसरे को बाह्य रूप से बिंदु P पर प्रतिच्छेद करते हैं। यदि AB = 4 सेमी, CD = 11 सेमी और PD = 15 सेमी है, तो PB की लम्बाई क्या है?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFदिया गया है:
AB और CD एक वृत्त के दो जीवाएं हैं जो एक-दूसरे को बाह्य रूप से बिंदु P पर प्रतिच्छेद करते हैं
AB = 4 सेमी, CD = 11 सेमी और PD = 15 सेमी
उपयोग किया गया सूत्र :
यदि दो जीवाएं AB और CD एक-दूसरे को बाह्य बिंदु P पर प्रतिच्छेद करते हैं तब,
PA × PB = PC × PD
गणना :
माना PA की लम्बाई 'x' है।
PC = PD - CD
⇒ 15 - 11
⇒ PC = 4 सेमी
प्रश्न के अनुसार
PA × PB = PC × PD
x × (x + 4) = 4 × 15
⇒ x = 6
PB = PA + AB
⇒ 6 + 4
⇒ 10
∴ PB की लम्बाई 10 सेमी है।
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