This question was previously asked in
RRB NTPC Graduate Level CBT-I Official Paper (Held On: 09 Jun, 2025 Shift 1)
View all RRB NTPC Papers >
  1. 176
  2. 119
  3. 196
  4. 19

Answer (Detailed Solution Below)

Option 2 : 119
Free
RRB NTPC Graduate Level Full Test - 01
100 Qs. 100 Marks 90 Mins

Detailed Solution

Download Solution PDF

दिया गया है:

यदि x - (1/x) = 3, तो x4 + (1/x4) का मान ज्ञात कीजिए।

प्रयुक्त सूत्र:

1. (x - 1/x) = a ⇒ (x2 + 1/x2) = a2 + 2

2. (x4 + 1/x4) = (x2 + 1/x2)2 - 2

गणना:

दिया गया है x - (1/x) = 3

⇒ x2 + 1/x2 = (3)2 + 2

⇒ x2 + 1/x2 = 9 + 2

⇒ x2 + 1/x2 = 11

अब, x4 + 1/x4 = (x2 + 1/x2)2 - 2

⇒ x4 + 1/x4 = (11)2 - 2

⇒ x4 + 1/x4 = 121 - 2

⇒ x4 + 1/x4 = 119

इसलिए, सही उत्तर विकल्प (2) है।

Latest RRB NTPC Updates

Last updated on Jul 21, 2025

-> RRB NTPC UG Exam Date 2025 released on the official website of the Railway Recruitment Board. Candidates can check the complete exam schedule in the following article. 

-> SSC Selection Post Phase 13 Admit Card 2025 has been released @ssc.gov.in

-> The RRB NTPC Admit Card CBT 1 will be released on its official website for RRB NTPC Under Graduate Exam 2025.

-> The RRB NTPC 2025 Notification released for a total of 11558 vacancies. A total of 3445 Vacancies have been announced for Undergraduate posts while a total of 8114 vacancies are announced for Graduate-level posts in the Non-Technical Popular Categories (NTPC).

-> Prepare for the exam using RRB NTPC Previous Year Papers.

-> UGC NET June 2025 Result has been released by NTA on its official site

More Algebra Questions

Hot Links: all teen patti teen patti real money app teen patti online game teen patti rules