निम्नलिखित व्यंजक को सरल कीजिए:

9993 × 10007

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RRB Technician Grade III Official Paper (Held On: 29 Dec, 2024 Shift 3)
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  1. 99999951
  2. 9999951
  3. 9999949
  4. 91999949

Answer (Detailed Solution Below)

Option 1 : 99999951
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दिया गया है:

सरलीकरण हेतु व्यंजक: 9993 × 10007

प्रयुक्त सूत्र:

बीजीय सर्वसमिका (a - b)(a + b) = a 2 - b का उपयोग करके

गणना:

यहाँ, a = 10000 और b = 7

⇒ 9993 × 10007 = (10000 - 7) × (10000 + 7)

⇒ 9993 × 10007 = 100002 - 72

⇒ 9993 × 10007 = 100000000 - 49

⇒ 9993 × 10007 = 99999951

सही उत्तर विकल्प 1 है।

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