\(\left| {\begin{array}{*{20}{c}} 1&1&1\\ 1&{1 + {\rm{a}}}&1\\ {1 + {\rm{b}}}&1&1 \end{array}} \right|\) का मूल्य क्या है?

  1. 0
  2. -ab
  3. ab
  4. इनमें से कोई भी नहीं

Answer (Detailed Solution Below)

Option 2 : -ab
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Detailed Solution

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धारणा:

प्राथमिक पंक्ति या स्तंभ रूपांतरण आव्यूह के सारणिक के मूल्य को नहीं बदलते हैं।

गणना:

\(\left| {\begin{array}{*{20}{c}} 1&1&1\\ 1&{1 + {\rm{a}}}&1\\ {1 + {\rm{b}}}&1&1 \end{array}} \right|\)

R2 → R2 – R1, R3 → R3 – Rलागू करके हमें मिलता है

\(\left| {\begin{array}{*{20}{c}} 1&1&1\\ 0&{\rm{a}}&0\\ {\rm{b}}&0&0 \end{array}} \right|\)

अब C3 के साथ विस्तार करके

= 1 (0 – ab) – 0 + 0 = -ab

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