Question
Download Solution PDFn = 4 के साथ समलम्बाकार नियम का उपयोग करके
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFअवधारणा:
जहाँ,
b = ऊपरी सीमा, a = निचली सीमा, h = चरण आकार।
समलम्बाकार नियम के अनुसार
दिया हुआ:
n = 4, a = 0, b = 2,
y = f(x) =
| x | x0 = 0 | x1 = 0.5 | x2 = 1 | x3 = 1.5 | x4 = 2 |
| y = f(x) | y0 = 1 | y1 = 0.67 | y2 = 0.5 | y3 = 0.4 | y4 = 0.33 |
I =
I = 0.25[(1 + 0.33) + 2(0.67 + 0.5 + 0.4)]
I = 0.25 [1.33 + 3.14]
I = 0.25 × 4.47
I = 1.1175
Last updated on Jun 23, 2025
-> The Document Verification for BPSC Assistant Professor (Advt. No. 04/2025 to 28/2025) will be conducted between 7th July 2025 to 24th July 2025
-> The BPSC Assistant Professor Notification 2025 was released for 1711 vacancies under Speciality (Advt. No.04/2025 to 28/2025).
-> The recruitment is ongoing for 220 vacancies (Advt. No. 01/2024 to 17/2024).
-> The salary under BPSC Assistant Professor Recruitment is approximately Rs 15600-39100 as per Pay Matrix Level 11.
-> The selection is based on the evaluation of academic qualifications & work experience and interview.
-> Prepare for the exam using the BPSC Assistant Professor Previous Year Papers. For mock tests attempt the BPSC Assistant Professor Test Series.