How many of the following numbers are fully divisible by 132?

264, 396, 462, 792, 968, 2178, 5184, 6336

Given:

Numbers to check for divisibility by 132: 264, 396, 462, 792, 968, 2178, 5184, 6336

Formula Used:

A number is fully divisible by 132 if the remainder of its division by 132 is 0.

Calculations:

For 264:

⇒ 264 ÷ 132 = 2 (Remainder = 0)

For 396:

⇒ 396 ÷ 132 = 3 (Remainder = 0)

For 462:

⇒ 462 ÷ 132 = 3 with a remainder of 66 (Not fully divisible)

For 792:

⇒ 792 ÷ 132 = 6 (Remainder = 0)

For 968:

⇒ 968 ÷ 132 = 7 with a remainder of 44 (Not fully divisible)

For 2178:

⇒ 2178 ÷ 132 = 16 with a remainder of 86 (Not fully divisible)

For 5184:

⇒ 5184 ÷ 132 = 39 with a remainder of 36 (Not fully divisible)

For 6336:

⇒ 6336 ÷ 132 = 48 (Remainder = 0)

The numbers fully divisible by 132 are 264, 396, 792, and 6336.

∴ There are 4 numbers that are fully divisible by 132.