How many words can be formed the letters of the word 'DAUGHTER' so that the vowels always come together ?

  1. 4320
  2. 4430
  3. 4530
  4. None of these

Answer (Detailed Solution Below)

Option 1 : 4320
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Detailed Solution

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Concept:

The number of ways to arrange n distinct things taken all at a time is given by: \({\;^n}{P_n} = n!\)

Calculation:

Given: 'DAUGHTER'

No. of distinct letters in the word 'DAUGHTER' = 8

Vowels in the word 'DAUGHTER' are A, E, U

No. of vowels in the word 'DAUGHTER' = 3

Consider the vowels as one group i.e (A, E, U), D, G, H, T, R then there are 6 letters which needs to be arranged.

As we know that, the  number of ways to arrange n distinct things taken all at a time is given by: \({\;^n}{P_n} = n!\)

∴ No. of ways to arrange 6 letters = 6!

∵ There are 3 vowels in the group formed.

So, number of ways to arrange these vowels = 3!

∴ The required no. of words = 6! × 3! = 4320

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