Hybridization of below compound is indicated by which option?

CH₃ - C ≡ N

Question

Question

This question was previously asked in

DSSSB PGT Chemistry (Female) Official Paper (Held On: 06 Jul, 2018 Shift 1)

Answer 1

CONCEPT:

Hybridization

Hybridization is the process of mixing atomic orbitals to form new hybrid orbitals that are suitable for bonding. The type of hybridization depends on the number of regions of electron density (bonds and lone pairs) around the central atom.
The types of hybridizations are:
- sp³: Four regions of electron density (e.g., single bonds).
- sp²: Three regions of electron density (e.g., one double bond and two single bonds).
- sp: Two regions of electron density (e.g., one triple bond or two double bonds).

EXPLANATION:

In the given compound, CH₃ - C≡N:
- The carbon in CH₃ (methyl group) is attached to three hydrogen atoms and one carbon atom through single bonds. Hence, it has four regions of electron density, and its hybridization is sp³.
- The central carbon (C) is bonded to one carbon atom (from CH₃) and one nitrogen atom through a triple bond. A triple bond counts as one region of electron density, and the single bond with the CH₃ group adds another region of electron density. Therefore, it has two regions of electron density, and its hybridization is sp.
- The nitrogen atom is involved in a triple bond with the central carbon atom, and it has one lone pair of electrons. This gives it two regions of electron density, and its hybridization is sp.

Final Hybridization CH₃: sp³ Central C: sp N: sp

Therefore, the correct answer is Option 4: sp³ sp sp.