If (3 + 2√5)2 = 29 + K√5, then what is the value of K?

This question was previously asked in
SSC CPO Tier- I Previous Paper 12 (Held on: 6th July 2017 Shift 2) 
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  1. 12
  2. 6
  3. 29
  4. 39

Answer (Detailed Solution Below)

Option 1 : 12
Free
SSC CPO : General Intelligence & Reasoning Sectional Test 1
50 Qs. 50 Marks 35 Mins

Detailed Solution

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Method I: (3 + 2√5)2

= (32 + (2√5)2 + 2 × 3 × 2√5)

= 9 + 20 + 12√5 = 29 + 12√5

On comparing, 29 + 12√5 = 29 + K√5

we get,

K = 12

 Alternate Method 

29 + 12√5 = 29 + K√5

⇒ K√5 = 29 - 29 + 12√5

⇒ K√5 = 12√5

∴ K = 12

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