Question
Download Solution PDFIf a, b, c, x, y, z are real numbers such that (a + b + c)2 - 3(ab + bc + ca) + 3(x2 + y2 + z2) = 0, then which one of the following is correct?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFGiven:
(a + b + c)2 - 3(ab + bc + ca) + 3(x2 + y2 + z2) = 0
Calculation:
We have
(a + b + c)2 - 3(ab + bc + ca) + 3(x2 + y2 + z2) = 0
We solve this question by options
If we put the value of option 3 then
a = b = c = k (let) and x = y = z = 0
(k + k + k)2 - 3(k2 + k2 + k2) + 3(0)
⇒ (3k)2 - 3(3k2)
⇒ 9k2 - 9k2 = 0
∴ The correct option is 3.
Last updated on Jun 26, 2025
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