If g1 is the gravitational acceleration of the earth at a height equal to half of the radius of the earth and g2 is the gravitational acceleration of the earth at a depth equal to half of the radius of the earth, then find the ratio of the g1 to g2.

  1. 4 : 9
  2. 8 : 9
  3. 9 : 8
  4. None of these

Answer (Detailed Solution Below)

Option 2 : 8 : 9
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Detailed Solution

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CONCEPT:

Acceleration Due to Gravity:

  • The force of attraction exerted by the earth on a body is called gravitational pull or gravity.
  • We know that when a force acts on a body, it produces acceleration. Therefore, a body under the effect of gravitational pull must accelerate.
  • The acceleration produced in the motion of a body under the effect of gravity is called acceleration due to gravity, it is denoted by g.
  • The acceleration due to gravity on the surface of the earth is given by,

  • The acceleration due to gravity above the surface of the earth is given as,

If h <<< R

  • The acceleration due to gravity below the surface of the earth is given as,

CALCULATION:

  • The gravitational acceleration of the earth at a height equal to half of the radius of the earth is given as (h = R/2),

     -----(1)

  • The gravitational acceleration of the earth at a depth equal to half of the radius of the earth is given as (d = R/2),

     -----(2)

By equation 1 and equation 2,

  • Hence, option 2 is correct.

Additional Information

  • The acceleration due to gravity below the surface of the earth is given as,
  • Let M be the mass of the earth, R be the radius of the earth gd be gravitational acceleration at depth d from the earth surface
  • g be gravitational acceleration on the earth's surfaces.
  • ρ  be the density of the earth.
  • P be the point inside the earth at depth d from earth surfaces.

∴ CS - CP = d, ∴ CP = R - d      ..............(1) (since CS = R)

∴ g = 

∴  .............(2)

 

gd = acceleration due to gravity at depth 'd'

∴ 

∴  ..........(3)

Dividing eq. (3) by eq (2)

∴ 

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