Question
Download Solution PDFIf the first day of 1812 was a Wednesday, what day was the last day of that year?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFThe year 1812 was a leap year, which means it had 366 days.
If January 1st, 1812 was a Wednesday,
Number of days after January 1st = days.
Now, we find the remainder of 365 when divided by 7:
365 ÷ 7 = 52 with a remainder of 1.
This means the day of the week will shift forward by 1 day from Wednesday.
Therefore, the last day of 1812 was a Thursday.
Hence, the correct answer is "Option 4".
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