Question
Download Solution PDFIf the member is denoted by m and joints by j , the condition for a frame to be redundant is given by:
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFExplanation:
m > 2j − 3
- This is the condition for a redundant (statically indeterminate) plane truss.
- When the number of members exceeds what is required for static determinacy, the structure becomes statically indeterminate.
- In such cases, additional compatibility equations are required to solve internal forces.
Additional Informationm < 2j − 3
- This condition indicates a mechanism or unstable structure, where the number of members is insufficient to maintain structural integrity.
- Such frames will not be able to carry loads effectively without deformation.
-
- Condition for a perfect (just-rigid) frame:
-
- Redundant (over-rigid) frame:
-
- Deficient (unstable) frame:
Last updated on Jul 1, 2025
-> JKSSB Junior Engineer recruitment exam date 2025 for Civil and Electrical Engineering has been rescheduled on its official website.
-> JKSSB JE exam will be conducted on 31st August (Civil), and on 24th August 2025 (Electrical).
-> JKSSB JE application form correction facility has been started. Candidates can make corrections in the JKSSB recruitment 2025 form from June 23 to 27.
-> JKSSB JE recruitment 2025 notification has been released for Civil Engineering.
-> A total of 508 vacancies has been announced for JKSSB JE Civil Engineering recruitment 2025.
-> JKSSB JE Online Application form will be activated from 18th May 2025 to 16th June 2025
-> Candidates who are preparing for the exam can access the JKSSB JE syllabus PDF from official website of JKSSB.
-> The candidates can check the JKSSB JE Previous Year Papers to understand the difficulty level of the exam.
-> Candidates also attempt the JKSSB JE Mock Test which gives you an experience of the actual exam.