If the number of turns in the coil is increased, then the induced emf in the coil will:

  1. Increase
  2. Decrease
  3. Remains same
  4. None of these

Answer (Detailed Solution Below)

Option 1 : Increase
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Detailed Solution

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CONCEPT:

Faraday's first law of electromagnetic induction:

  • Whenever a conductor is placed in a varying magnetic field, an electromotive force is induced.
  • If the conductor circuit is closed, a current is induced which is called induced current.

Faraday's second law of electromagnetic induction:

  • The induced emf in a coil is equal to the rate of change of flux linked with the coil.

\(⇒ e=-N\frac{d\text{ }\!\!\Phi\!\!\text{ }}{dt}\)

Where N = number of turns, dΦ = change in magnetic flux and e = induced e.m.f.

  • The negative sign says that it opposes the change in magnetic flux which is explained by Lenz law.


EXPLANATION:

  • From Faraday's second law of electromagnetic induction, the induced emf in a coil is equal to the rate of change of flux linked with the coil.

\(⇒ e=-N\frac{d\text{ }\!\!\Phi\!\!\text{ }}{dt}\)

⇒ e ∝ N     -----(1)

Where N = number of turns, dΦ = change in magnetic flux and e = induced e.m.f.

  • By equation 1 it is clear that the induced emf is directly proportional to the number of turns, so if the number of turns in the coil is increased, then the induced emf in the coil will also increase.
  • Hence, option 1 is correct.
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