If the origin and the points P(2, 3, 4), Q(1, 2, 3) and R(x, y, z) are co-planar then

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  1. x - 2y - z = 0
  2. x + 2y + z = 0
  3. x - 2y + z = 0
  4. 2x - 2y + z = 0

Answer (Detailed Solution Below)

Option 3 : x - 2y + z = 0
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Detailed Solution

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Concept:

If the three vectors are coplanar then their scalar triple product is zero..

\(\rm \vec a.(\vec b\times \vec c) = 0\)

 

Calculations:

Given the origin (0, 0, 0) and the points P(2, 3, 4), Q(1, 2, 3) and R(x, y, z) are co-planer

⇒ \(\rm \vec a = \vec {OR} = {(x, y, z)}\)

⇒ \(\rm \vec b = \vec {OP} = {(2, 3, 4)}\)

⇒ \(\rm \vec c = \vec {OQ} = {(1, 2, 3)}\)

Here, \(\rm\vec a\)\(\rm\vec b\) and \(\vec c\)are co planer

The three vectors are coplanar if their scalar triple product is zero..

\(\rm \vec a.(\vec b\times \vec c) = 0\)

\(\begin{vmatrix} \rm x & \rm y & \rm z\\ 2&3 &4 \\ 1&2 &3 \end{vmatrix} = 0\)

⇒ x(9 - 8) - y(6 - 4) + z (4 - 3) = 0

⇒ x - 2y + z = 0

Hence, if the origin and the points P(2, 3, 4), Q(1, 2, 3) and R(x, y, z) are co-planar then x - 2y + z = 0

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