In a class\(\frac{3}{4}\) of the students are girls and rest are boys. If \(\frac{2}{3}\)of the girls and \(\frac{1}{2} \) of the boys are absent, what part of the total number of students are present?

Given:

Fraction of girls = (3/4)

Fraction of boys = (1 - 3/4) = (1/4)

Fraction of absent girls = (2/3)

Fraction of absent boys = (1/2)

Formula used:

Part of students present = Total students × [Fraction of girls × (1 - Fraction of absent girls) + Fraction of boys × (1 - Fraction of absent boys)]

Calculation:

Let the total students = 1 

Fraction of girls present = (3/4) × (1 - 2/3)

⇒ (3/4) × (1/3) = (1/4)

Fraction of boys present = (1/4) × (1 - 1/2)

⇒ (1/4) × (1/2) = (1/8)

Total fraction of students present = Fraction of girls present + Fraction of boys present

⇒ (1/4) + (1/8)

⇒ (2/8) + (1/8) = (3/8)

∴ The correct answer is option (2).