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In a group of 6 persons of unequal heights, D is shorter than A and C, but taller than E and F. Two persons are taller than B, and one person is shorter than E. Which of the following inferences is NOT NECESSARILY valid?

  1. A is the tallest of all.
  2. C is taller than B.
  3. F is the shortest of all.
  4. B is taller than D.

Answer (Detailed Solution Below)

Option 1 : A is the tallest of all.

Detailed Solution

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<p><strong>Given:</strong></p><p>D is shorter than A and C, but taller than E and F.</p><p>Two persons are taller than B.</p><p>One person is shorter than E.</p><p><b>Explanation</b></p><p>1. D is shorter than A and C, but taller than E and F.</p><p>A, C > D > E, F (from the first statement)</p><p>2. Two persons are taller than B, and one person is shorter than E.</p><p>_ > _ > B > _ > E > _</p><p>The best possible arrangement from the above statement 1 and statement 2 will be </p><p><span>Case 1:-<strong> A > C</strong></span><strong><span> > B</span><span> > D</span><span> > E > F</span></strong></p><p>OR</p><p><span>Case 2:- <strong>C > A</strong></span><strong><span> > B</span><span> > D</span><span> > E > F</span></strong></p><p>Now let's analyze the options:</p><p>1) <strong>A is the tallest of all.</strong><br> This cannot be necessarily valid since C could be the tallest.</p><p>2) <strong>C is taller than B.</strong><br> This is valid in both possible arrangements.</p><p>3) <strong>F is the shortest of all.</strong><br> <span>This is valid in both possible</span><span> arrangements.</span></p><p>4) <strong>B is taller than D.</strong><br> <span>This is valid in both possible</span><span> arrangements.</span></p><p><strong>Therefore, the correct answer is</strong> : Option 1</p> - www.lessoinsdecolette.com
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