In Mendel's experiments, the dihybrid phenotypic ratio was 

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  1. 9 (Round, Green) : 3 (Round, Yellow) : 3 (Wrinkled, Yellow): 1 (Wrinkled, Green).
  2. 9 (Round, Yellow) : 3 (Round, Green) : 3 (Wrinkled, Yellow): 1 (Wrinkled, Green).
  3. 9 (Wrinkled, Yellow) : 3 (Round, Green) : 3 (Round, Yellow) : 1 (Wrinkled, Green).
  4. 9 (Wrinkled, Green) : 3 (Round, Yellow): 3 (Wrinkled, Yellow): 1 (Round, Green).

Answer (Detailed Solution Below)

Option 2 : 9 (Round, Yellow) : 3 (Round, Green) : 3 (Wrinkled, Yellow): 1 (Wrinkled, Green).
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Key Points
  • Gregor Mendel is known as the Father of Genetics as he gave the Principles of Inheritance that formed the basis of genetics.
  • His experiments involved plant hybridizations on garden pea plant.
  • Dihybrid cross - is a cross or hybridization between 2 parents differing in 2 traits.
  • Each of the traits had 2 distinct phenotypic characters - one dominant, one recessive.

Explanation:

  • Mendel chose 2 traits:
    • Seed shape - Round (dominant) and wrinkled (recessive).
    • Seed color - Yellow (dominant) and green (recessive).
  • From the cross between these 2 parental generation plants, he obtained the F1 generation where all plants had Round, Yellow seeds.
  • These F1 plants were self-fertilized to get the F2 generation.
  • The phenotypic and genotypic ratios are then observed from the F2 generation.

F2 Vinanti Teaching 29.06.23 D1

Important Points

  • The characters can be expressed in homozygous or heterozygous conditions:
    • Yellow - YY, Yy
    • Green - yy
    • Round - RR, Rr
    • Wrinkled - rr
  • The characters in the F2 generation were expressed in the proportions given above.
  • Thus, we can get the phenotypic ratio of this dihybrid cross as:

9 (Round, Yellow) : 3 (Round, Green) : 3 (Wrinkled, Yellow): 1 (Wrinkled, Green)

  • We get 4 phenotypes from a dihybrid cross.
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