In the given circuit, the charge on 4 μF capacitor will be:

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JEE Mains Previous Paper 1 (Held On: 12 Apr 2019 Shift 2)
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  1. 5.4 μC
  2. 9.6 μC
  3. 13.4 μC
  4. 24 μC

Answer (Detailed Solution Below)

Option 4 : 24 μC
Free
JEE Main 04 April 2024 Shift 1
90 Qs. 300 Marks 180 Mins

Detailed Solution

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Concept:

Parallel capacitor allow the charge a choice of capacitors potential difference is the same with multiple parallel capacitors.

Calculation:

The elaborate figure of the given diagram is:

The total of the parallel capacitor:

⇒ Cp = 1μ + 5μ = 6μF

We know that,

Where,

q = Charge

V = Voltage

Now,

Now, the total voltage is:

V = V1 + V2

∴ q = 24 μC

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