In transverse fillet, welded joint, the size of weld is equal to

Explanation:

Transverse fillet weld:

Let t is the throat length and h is the thickness of weld.

\(t={h\over (cos⁡ θ+sin⁡\theta )}\)

Ps = P sin θ

\(\begin{array}{l} \tau = \frac{{{P_s}\left( {\sin \theta + \cos \theta } \right)}}{{hl}} = \frac{{P\sin \theta \left( {\sin \theta + \cos \theta } \right)}}{{hl}}\\ \frac{{\partial \tau }}{{\partial \theta }} = 0 \Rightarrow \theta = 67.5^\circ \end{array}\)

The condition for the plane with the maximum shear stress is θ = 67.5° for transverse fillet weld.

\(​​t={h\over (cos⁡θ+sin⁡ϑ )}\)

put \(θ=67.5\) in the above equation

we get

\(t={h\over (cos⁡67.5+sin⁡67.5 )}\)

\(t={h\over1.3065}\)

\(h=1.3065 t\)

\(h≈ √2 t\)​​