Question
Download Solution PDFഒരു വൃത്തസ്തൂപികയുടെ ഉയരവും, ചരിഞ്ഞ ഉയരവും യഥാക്രമം 20 സെന്റിമീറ്ററും 25 സെന്റിമീറ്ററുമാണ്, വൃത്തസ്തൂപികയുടെ വ്യാപ്തം കണ്ടെത്തുക.
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFതന്നിരിക്കുന്നത്:
വൃത്തസ്തൂപികയുടെ ഉയരം = 20 സെ.മീ.
വൃത്തസ്തൂപികയുടെ ചരിഞ്ഞ ഉയരം = 25 സെ.മീ.
സൂത്രവാക്യം:
വൃത്തസ്തൂപികയുടെ വ്യാപ്തം = [1/3]πr2h
l2 = r2 + h2
കണക്കുകൂട്ടൽ:
ചോദ്യത്തിനനുസരിച്ച്,
252 = r2 + 202
⇒ 625 = r2 + 400
⇒ r2 = 625 – 400
⇒ r2 = 225
⇒ r = 15
∴ വൃത്തസ്തൂപികയുടെ വ്യാപ്തം = [1/3] × π × 15 × 15 × 20 = 1500π
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