Question
Download Solution PDFABCD एक समभुज चौकोन आहे, जेथे कर्ण AC आणि BD हे 'O' आणि ∠OBA = 25° वर छेदतात. ∠BCD चे मूल्य शोधा.
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFदिलेल्याप्रमाणे:
∠OBA = 25°
वापरलेली संकल्पना:
समभुज चौकोनाचा कर्ण 90° वर छेदतो
समभुज चौकोनाचे विरुद्ध कोन समान असतात
समभुज चौकोनाच्या समीप कोनांची बेरीज 180° असते.
समभुज चौकोनाचा कर्ण कोनाचे द्विभाजन करतो
गणना:
कर्ण कोनाचे द्विभाजन करतो
⇒ ∠ABC = 2 × ∠OBA
⇒ ∠ABC = 2 × 25°
⇒ ∠ABC = ५०°
समभुज चौकोनाच्या समीप कोनांची बेरीज = ∠ABC + ∠BCD
⇒ 50° + ∠BCD = 180°
⇒ ∠BCD = 180° - 50°
⇒ ∠BCD = 130°
∴ BCD चे माप 130° आहे
Last updated on Apr 30, 2025
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