The distance between the lines y = 2x + 3 and y = 2x + 4 is

  1. 1
  2. \(\rm \frac{1}{\sqrt{5}}\)
  3. \(\rm \frac{7}{\sqrt{5}}\)
  4. \(\rm \frac{-7}{\sqrt{5}}\)

Answer (Detailed Solution Below)

Option 2 : \(\rm \frac{1}{\sqrt{5}}\)
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Detailed Solution

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Concept:

Distance between two parallel lines:

The distance d between two parallel lines y = mx + c1 and y = mx + c2 is given by d = \(\rm \frac{\left | c_{2} - c_{1} \right |}{\sqrt{1 + m^{2}}}\)

Calculation:

Given equation of lines are y = 2x + 3 and y = 2x + 4

Perpendicular distance = \(\rm \frac{\left | 4 - 3 \right |}{\sqrt{1 + 2^{2}}}\) = \(\rm \frac{1}{\sqrt{5}}\)

The distance between the lines y = 2x + 3 and y = 2x + 4 is \(\rm \frac{1}{\sqrt{5}}\)

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