The distance between two parallel lines 5x - 12y + 2 = 0 and 5x - 12y - 3 = 0 is given by:

  1. 1/17
  2. 5/13
  3. 1/13
  4. 5/14

Answer (Detailed Solution Below)

Option 2 : 5/13
Free
Army Havildar SAC - Quick Quiz
2 K Users
5 Questions 10 Marks 6 Mins

Detailed Solution

Download Solution PDF

Concept:

The distance between two parallel lines ax + by + c1 = 0 and ax + by + c2 = 0 is given by the formula: \(\rm d=\dfrac{|c_1-c_2|}{\sqrt{a^2+b^2}}\).

 

Calculation:

Using the concept above, we have a = 5, b = -12, c1 = 2 and c2 = -3.

∴ \(\rm d=\dfrac{|c_1-c_2|}{\sqrt{a^2+b^2}}\)

\(\rm \dfrac{|2-(-3)|}{\sqrt{5^2+(-12)^2}}\)

\(\rm \dfrac{|5|}{\sqrt{169}}\)

\(\dfrac{5}{13}\).

Latest Army Havildar SAC Updates

Last updated on Jul 1, 2025

-> The Indian Army has released the Exam Date for Indian Army Havildar SAC (Surveyor Automated Cartographer).

->The Exam will be held on 9th July 2025.

-> Interested candidates had applied online from 13th March to 25th April 2025.

-> Candidates within the age of 25 years having specific education qualifications are eligible to apply for the exam.

-> The candidates must go through the Indian Army Havildar SAC Eligibility Criteria to know about the required qualification in detail. 

More Lines Questions

Get Free Access Now
Hot Links: teen patti king teen patti real cash apk teen patti master plus teen patti casino download