Question
Download Solution PDFComprehension
Directions: Study the following information carefully and answer the questions.
The given table DI shows the total number of passengers (male and female) who travelled in trains A and B, as well as the number of passengers who travelled in train A.
| Days | Total number of passengers who travelled in trains A and B together | Out of the total number of passengers, the fraction of passengers who travelled by train A |
| Monday | 165 | 7/11 |
| Tuesday | 135 | 2/5 |
| Wednesday | 180 | 8/15 |
| Thursday | 144 | 3/8 |
The number of female passengers who travelled in train B on Thursday is 25% more than the number of male passengers who travelled in the same train on the same day. Find the number of male passengers in train B on Thursday.
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFGeneral Solution:
| Day | Total Passengers | Fraction in Train A | Passengers in Train A | Passengers in Train B |
|---|---|---|---|---|
| Monday | 165 | 7/11 | 165 × 7 ÷ 11 = 105 | 165 - 105 = 60 |
| Tuesday | 135 | 2/5 | 135 × 2 ÷ 5 = 54 | 135 - 54 = 81 |
| Wednesday | 180 | 8/15 | 180 × 8 ÷ 15 = 96 | 180 - 96 = 84 |
| Thursday | 144 | 3/8 | 144 × 3 ÷ 8 = 54 | 144 - 54 = 90 |
Calculations:
We are given:
Total passengers in Train B on Thursday = 90 (from general solution)
Female passengers are 25% more than male passengers in Train B on Thursday
Let male passengers = x
⇒ Female passengers = 1.25x
⇒ Total in Train B on Thursday = x + 1.25x = 2.25x
⇒ 2.25x = 90
⇒ x = 90 ÷ 2.25 = 40
Thus, 40 male passengers travelled in train B on Thursday.
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