Question
Download Solution PDFThe octahedral diamagnetic low spin complex among the following is
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AIIMS BSc NURSING 2024 Memory-Based Paper
Answer (Detailed Solution Below)
Option 4 : [Co(NH3)6)3+
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AIIMS BSc NURSING 2024 Memory-Based Paper
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Detailed Solution
Download Solution PDFCONCEPT:
Diamagnetism and Low Spin Complexes
- Diamagnetic complexes have all paired electrons, resulting in no net magnetic moment.
- In octahedral complexes, the electronic configuration can be influenced by the nature of ligands, leading to high spin or low spin configurations.
- Strong field ligands such as CN- and NH3 cause pairing of electrons, resulting in low spin complexes.
EXPLANATION:
- [NiCl4]2-:
- Nickel (Ni2+) has a d8 configuration.
- Chloride (Cl-) is a weak field ligand, leading to a high spin complex.
- High spin d8 configuration in a tetrahedral field does not result in a diamagnetic complex.
- [CoCl6]3-:
- Cobalt (Co3+) has a d6 configuration.
- Chloride (Cl-) is a weak field ligand, leading to a high spin complex.
- High spin d6 configuration in an octahedral field does not result in a diamagnetic complex.
- [CoF6]3-:
- Cobalt (Co3+) has a d6 configuration.
- Fluoride (F-) is a weak field ligand, leading to a high spin complex.
- High spin d6 configuration in an octahedral field does not result in a diamagnetic complex.
- [Co(NH3)6]3+:
- Cobalt (Co3+) has a d6 configuration.
- Ammonia (NH3) is a strong field ligand, leading to a low spin complex.
- Low spin d6 configuration in an octahedral field results in all paired electrons, making it diamagnetic.
Therefore, the octahedral diamagnetic low spin complex among the given options is [Co(NH3)6]3+.
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